x^2-14580x+87489=0

Solution for x^2-14580x+87489=0 equation:

x^2-14580x+87489=0

a = 1; b = -14580; c = +87489;
Δ = b2-4ac
Δ = -145802-4·1·87489
Δ = 212226444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{212226444}=\sqrt{36*5895179}=\sqrt{36}*\sqrt{5895179}=6\sqrt{5895179}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14580)-6\sqrt{5895179}}{2*1}=\frac{14580-6\sqrt{5895179}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14580)+6\sqrt{5895179}}{2*1}=\frac{14580+6\sqrt{5895179}}{2}
$